
How Much Does it Cost to Run an LED bulb?
- News
- 16 Jun, 2017
The main advantage of upgrading to LED lighting is that the running costs are significantly lower than traditional lighting such as halogen or incandescent. These savings could be up to 90%. This being said though, do you know the actual cost to run LED bulbs? Today we going to answer this question.
We have 6W Led bulbs that are replacements for 60W halogen bulbs, again saving 90% energy and cost.
Now you can apply this to the bulbs in your home no matter if they’re LED or not. 5W GU10 LED; (5/1000) x 1 x 14p = 0.07p per hour to run 50W GU10 halogen; (50/1000 x 1 x 14p = 0.7p per hour to run
How do you work out the cost of electricity?
Before we can work out the cost of running an LED bulb we first should look at how the cost of electricity is worked out. Mains electricity is measured kilowatt hours (kWh) so the more kWh you use the more you’ll pay. The actual cost can be worked out as follows: COST = NUMBER OF kWh x COST PER kWh. Your cost per kWh will depend on your provider. This could be up to 17p if you pay quarterly (rather than by direct debit), so we’ll use an average of 14p for this article. Different electrical appliances individually use different amounts of electricity. This is illustrated by their wattage (W). The higher the wattage of the item the more electricity it uses. For example, a hair dryer can be 1,200W (1.2kW) compared to a radio using 10W, meaning the hair dryer uses considerably more energy and thus costs more to run.The difference in wattage between traditional and LED bulbs
The large variance between an LED bulb and, say, a halogen bulb wattage is the reason LEDs are so much cheaper to run. To show the comparison, we have 5W LED spotlights that replace and produce the same light as a 50W halogen spotlight. This means that the LED spot uses 90% less electricity to run and therefore it costs 90% less.
How much does one LED bulb cost to run?
As you can tell there are several factors that dictate the running cost of a single bulb, but all of them fit into the formula below: